Consider the differential amplifier in Figure P11.17 with parameters V^ =5  V, V^-=-5  V, and IO=0.8  mA. Neglect base currents and assume VA=∞for all transistors. The emitter currents can be written as IE 1=IS 1 e^VB E 1 / VT and IE 2=IS 2 e^VA E 2 / VT. (a) If v1=v2=0 and IS 1= IS 2=3 ×10^-15  A, determine (vO 1-vO 2) for (i) RC 1=RC 2=7.5 k Ωand (ii) RC 1=7.4 k Ω, RC 2=7.6 k Ω. (b) Repeat part (a) for IS 1= 2.9 ×10^-15  A and IS 2=3.1 ×10^-15  A. | Numerade

For each of the emitter degenerated differential amplifiers (a ... | Filo