Calculate the Cyclomatic Complexity for the below Program in C , using the two methodsMethod 1: using the Flow Graph, and then the formula: CC = (E-N) 2Method 2: using the formula: CC = Number of Predicates 1Program.cppLine Number int main()0 int m=105, n=30, r; int n1=m, n2=n;1 if(n>m) 2 r=m;3 m=n;4 n=r;5 6 r = m%n;7 while(r != 0)8 m=n;9 n=r;10 r= m%n;11 12 cout<<"GCD of " << n1 << "and" << n2 << "is: " << n << end;13 return 0;

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SOLVED: Consider the following flow graph:5Based on this flow graph, calculate the cyclomatic complexity using two different methods. Based on the cyclomatic complexity value, derive the basis set of test paths.

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